Mathematical Challenge...

DarkMetal · Post by **DarkMetal** » Tue Jan 09, 2007 8:36 am

Ok guys, I've been racking my brain for quite a while trying to figure this out. Basically we have two numbers we can use, and we need to use those two numbers to create a formula for finding the third number. You can use the numbers as many times as you want, but you can only use the numbers provided as long as you find a trustworthy formula. I'll provide two sets of numbers for you to test your formula on.

Set #1:
using these two numbers:
36926104
33360
find this number:
14616

Set #2
using these two numbers:
38221976
44040
find this number:
25084

To anyone who participates, thankyou so much for your help.

Ketchup_Bomb · Post by **Ketchup_Bomb** » Tue Jan 09, 2007 9:01 am

We're not school teachers.

Sorry, but there isn't much of a reason for this being here.
Please could discuss it, but it doesn't really involve us.

Good luck though.

Edit: Unlocked... a little misunderstanding I would say.

Sorry for the confusion, and good luck with this one people!

DoorM4n · Post by **DoorM4n** » Tue Jan 09, 2007 3:15 pm

When I get home from class, I like to relax and ignore everything I had just been taught. (That includes math)

DarkMetal · Post by **DarkMetal** » Tue Jan 09, 2007 6:19 pm

The equation we're trying to find is for getting to the sbsp reflexive in the scnr meta. The first number is the scnr offset, the second is the scnr size. The number we're trying to find is the number of bytes into the scnr meta that the sbsp reflexive is located.

Ice Link · Post by **Ice Link** » Tue Jan 09, 2007 6:24 pm

hubana hubana?

xbox7887 · Post by **xbox7887** » Tue Jan 09, 2007 10:24 pm

bsp magic can be found by looking at the sbsp info in the scnr tag...it's all pretty well documented :X

Xero · Post by **Xero** » Wed Jan 10, 2007 7:40 am

turk645 · Post by **turk645** » Wed Jan 10, 2007 8:01 am

where did that 62 come from?

nintynine · Post by **nintynine** » Wed Jan 10, 2007 8:02 am

so you cant just say;
36926104+33360=14616x
where x = 2528.69896?

i used the first two numbers once and i used the last number 2528.69896 times?

Ketchup_Bomb · Post by **Ketchup_Bomb** » Wed Jan 10, 2007 8:29 am

It is a formula that will result to 14616 and 25084 respectively.
No variables; at least that's what I got out of it.

Kirk · Post by **Kirk** » Wed Jan 10, 2007 9:27 am

(a-a)+(b-b)+c.

Easy.

Ketchup_Bomb · Post by **Ketchup_Bomb** » Wed Jan 10, 2007 11:37 am

Nice Kirk. lol

-Legendary- · Post by **-Legendary-** » Wed Jan 10, 2007 7:26 pm

86463.1